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2x^2+31x+90=0
a = 2; b = 31; c = +90;
Δ = b2-4ac
Δ = 312-4·2·90
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{241}}{2*2}=\frac{-31-\sqrt{241}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{241}}{2*2}=\frac{-31+\sqrt{241}}{4} $
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